1 00:00:00,000 --> 00:00:06,000 Hello, my name is Ewa Salamończyk and I work at the Institute of Animal Science and Fisheries. 2 00:00:06,000 --> 00:00:09,000 Faculty of Agricultural Sciences at the University of Siedlce. 3 00:00:09,000 --> 00:00:15,000 I would like to present examples with solutions for the topic of optimizing matching plans. 4 00:00:15,000 --> 00:00:19,000 In breeding strategies using cattle as an example. 5 00:00:19,000 --> 00:00:21,000 Example first. 6 00:00:21,000 --> 00:00:28,000 Improvement of one production trait is carried out in a dairy cattle herd - milk yield in lactation. 7 00:00:28,000 --> 00:00:33,000 Three cows with known breeding values were allocated for mating. 8 00:00:33,000 --> 00:00:39,000 Let's assume that there are seeds from four bulls with known breeding values and varying prices, 9 00:00:39,000 --> 00:00:43,000 And each cow will be paired with a different bull. 10 00:00:43,000 --> 00:00:45,000 Assumptions. 11 00:00:45,000 --> 00:00:48,000 1 kg of milk equals 2 zł. 12 00:00:48,000 --> 00:00:56,000 With a 1% increase in inbreeding, milk production during lactation decreases by an average of 16 kg. 13 00:00:57,000 --> 00:00:59,000 Order of operations. 14 00:00:59,000 --> 00:01:08,000 First, the net present value is determined as the profit associated with obtaining offspring from each pairing. 15 00:01:08,000 --> 00:01:13,000 Secondly, all possible pairs of available individuals are created. 16 00:01:13,000 --> 00:01:17,000 The size of the set is determined by the number of females. 17 00:01:17,000 --> 00:01:24,000 Thirdly, the net present value of the descendants of each pair in the set is summed up. 18 00:01:24,000 --> 00:01:30,000 At the end, a cow-bull set is chosen to guarantee the highest profit. 19 00:01:30,000 --> 00:01:33,000 Data for the first example. 20 00:01:33,000 --> 00:01:45,000 3 cows with known breeding value in kilograms and 4 bulls with known breeding value and provided semen cost. 21 00:01:45,000 --> 00:01:51,000 Pedigrees of cows and bulls. 22 00:01:51,000 --> 00:02:00,000 Solution for choosing the cow-bull set to maximize profit. 23 00:02:00,000 --> 00:02:09,000 We use the following formula to calculate the net present value for computing the profit of each cow-bull set. 24 00:02:09,000 --> 00:02:18,000 Half of the breeding value sum of male and female from a selected set reduced by the size of inbreeding depression. 25 00:02:18,000 --> 00:02:24,000 the offspring from this set and the cost of purchasing semen from this bull. 26 00:02:24,000 --> 00:02:34,000 To calculate the level of inbreeding depression, you need to calculate the inbred offspring from a given mating using the following formula. 27 00:02:34,000 --> 00:02:46,000 Where N1 is the number of paths from a common ancestor to one parent, and N2 is the number of paths from a common ancestor to the other parent of the proband. 28 00:02:46,000 --> 00:02:51,000 from F-alpha to a common ancestor. 29 00:02:51,000 --> 00:02:58,000 The inbreeding coefficient of offspring from mating cow A and bull I is 0. 30 00:02:58,000 --> 00:03:05,000 The structural pedigrees of the cow A and bull I do not have common ancestors. 31 00:03:05,000 --> 00:03:11,000 Structural pedigrees of cow B and bull I do not have common ancestors. 32 00:03:11,000 --> 00:03:18,000 The inbreeding coefficient of the offspring of a cow C and a bull I is 0. 33 00:03:18,000 --> 00:03:24,000 The inbreeding coefficient of the offspring of cow A and bull II is 0. 34 00:03:24,000 --> 00:03:32,000 The inbreeding coefficient of the offspring of cow B and bull II is 0.3125. 35 00:03:32,000 --> 00:03:37,000 Pedigrees of the cow and bull are my common ancestor. 36 00:03:37,000 --> 00:03:45,000 The inbreeding coefficient of the offspring of cow C and bull II is 0.0625. 37 00:03:45,000 --> 00:03:55,000 The inbreeding coefficient of the offspring of cow A and bull III is 0.03125. 38 00:03:55,000 --> 00:04:03,000 The inbreeding coefficient of the offspring of cow B and bull III is 0.025. 39 00:04:03,000 --> 00:04:09,000 The inbreeding coefficient of the offspring of cow C and bull III is 0.125. 40 00:04:09,000 --> 00:04:19,000 The inbreeding coefficient of the offspring of cow A and bull IV is 0.025. 41 00:04:19,000 --> 00:04:28,000 The calculated coefficients of inbreeding for the offspring of each pair are listed in the table. 42 00:04:28,000 --> 00:04:33,000 The next step is to calculate the net present value NPV. 43 00:04:33,000 --> 00:04:40,000 indicating the magnitude of profit associated with producing offspring from each pairing. 44 00:04:40,000 --> 00:04:47,000 This is how the net NPV values ​​are calculated. 45 00:04:47,000 --> 00:04:53,000 Then all possible pairs of individuals are created using the available individuals. 46 00:04:53,000 --> 00:05:01,000 The size of the set is determined by the number of females. 47 00:05:01,000 --> 00:05:09,000 The NPV is summed up, i.e. the net present value, of the offspring of each PAR making up the set. 48 00:05:09,000 --> 00:05:25,000 The last element is the selection of cow-bull sets guaranteeing the highest profit. 49 00:05:25,000 --> 00:05:38,000 In conclusion, the highest profit can be obtained by mating the following visible sets of cow bull. 50 00:05:38,000 --> 00:05:40,000 Example two. 51 00:05:40,000 --> 00:05:47,000 Please create an individual mating plan for a black and white Polish Holstein-Friesian cow. 52 00:05:47,000 --> 00:05:54,000 Provide suggestions for matching three bulls from selected companies' bull catalogs. 53 00:05:54,000 --> 00:05:57,000 Using the latest estimates. 54 00:05:57,000 --> 00:06:06,000 Corrective alignment to improve the structure of the rear suspension. 55 00:06:06,000 --> 00:06:12,000 The cow's data and pedigree are visible on the slide. 56 00:06:12,000 --> 00:06:19,000 The cow received a total of 79 points in the assessment of type and conformation, therefore it was rated fairly well. 57 00:06:19,000 --> 00:06:24,000 The udder received 77 points. 58 00:06:24,000 --> 00:06:31,000 Detailed information on the values of cultivated traits and sub-indices is shown here. 59 00:06:31,000 --> 00:06:36,000 Index selection production functionality. 60 00:06:36,000 --> 00:06:40,000 Solution of example two. 61 00:06:40,000 --> 00:06:44,000 Use the latest catalogs with current bull evaluations. 62 00:06:44,000 --> 00:06:50,000 These directories contain rankings of bulls evaluated conventionally. 63 00:06:50,000 --> 00:06:53,000 or on daughters or genomically. 64 00:06:53,000 --> 00:06:57,000 Here is the list of bulls being evaluated conventionally: 65 00:06:57,000 --> 00:07:02,000 December 2023 Polish Holstein-Friesian cattle appraisal. 66 00:07:02,000 --> 00:07:07,000 The buffalo were arranged in order of their functional production index. 67 00:07:07,000 --> 00:07:14,000 Highest values and breeding values for production traits are also highlighted in colors. 68 00:07:14,000 --> 00:07:19,000 and the highest subindex values. 69 00:07:19,000 --> 00:07:24,000 Create a personalized plan for associating the sample. 70 00:07:24,000 --> 00:07:28,000 Select 3 bulls from the catalog. 71 00:07:28,000 --> 00:07:32,000 This is to be a corrective association that will aim to improve the structure of the exchange. 72 00:07:32,000 --> 00:07:35,000 Replace the rear suspension. 73 00:07:35,000 --> 00:07:39,000 We can start by using a selection of the best bulls. 74 00:07:39,000 --> 00:07:45,000 [i.e., including subindex of gender, and specifically listing subindexes. ] 75 00:07:45,000 --> 00:07:54,000 Referring to the subindex values, we can select bulls from positions 2, 3, and 6. 76 00:07:58,000 --> 00:08:01,000 To thoroughly understand the breeding value of these individuals, 77 00:08:01,000 --> 00:08:04,000 We find in the catalog cards of selected bulls. 78 00:08:04,000 --> 00:08:09,000 and we analyze information from line charts about the price of cut. 79 00:08:09,000 --> 00:08:12,000 especially in terms of potential improvement features 80 00:08:12,000 --> 00:08:16,000 And their offspring. 81 00:08:16,000 --> 00:08:21,000 Visible data of the griffin cow, position 3. 82 00:08:21,000 --> 00:08:27,000 Here the cow's data is collected, position 2. 83 00:08:27,000 --> 00:08:30,000 In the sixth position of the Czekan Mlek bullfight. 84 00:08:30,000 --> 00:08:34,000 Therefore, after a detailed analysis, these three presented buffaloes. 85 00:08:34,000 --> 00:08:37,000 Prices for custom sizes can be quoted upon request. 86 00:08:37,000 --> 00:08:41,000 to the fathers of the next generation of cows. 87 00:08:43,000 --> 00:08:48,000 Example 3. Please create an individual matching plan 88 00:08:48,000 --> 00:08:51,000 for the same Polish Holstein-Friesian cow 89 00:08:51,000 --> 00:08:54,000 Black and white varieties from the second example. 90 00:08:54,000 --> 00:08:58,000 Please provide an association suggestion with two bulls. 91 00:08:58,000 --> 00:09:01,000 selected from publicly available databases 92 00:09:01,000 --> 00:09:05,000 Institute of Animal Science (State Research Institute) 93 00:09:05,000 --> 00:09:09,000 Polish Federation of Cattle Breeders' Genetic Center 94 00:09:09,000 --> 00:09:11,000 Milk Producers. 95 00:09:11,000 --> 00:09:14,000 Corrective matching that aims to 96 00:09:14,000 --> 00:09:18,000 Improving the longevity of offspring. 97 00:09:18,000 --> 00:09:21,000 Solution of example three. 98 00:09:21,000 --> 00:09:25,000 Using the public database of the Genetics Center. 99 00:09:25,000 --> 00:09:28,000 Polish Federation of Cattle Breeders and Milk Producers 100 00:09:28,000 --> 00:09:31,000 we can choose conventionally rated bulls 101 00:09:31,000 --> 00:09:34,000 either by value or by ordering of values 102 00:09:34,000 --> 00:09:37,000 Functional production selection index 103 00:09:37,000 --> 00:09:40,000 and longevity. 104 00:09:40,000 --> 00:09:43,000 Checking if the seed is available 105 00:09:43,000 --> 00:09:46,000 Who can I order from? 106 00:09:46,000 --> 00:09:49,000 The slides are arranged in order of level. 107 00:09:49,000 --> 00:09:52,000 breeding value for longevity 108 00:09:52,000 --> 00:09:56,000 Features included in the production functionality index. 109 00:09:56,000 --> 00:10:00,000 Similarly to catalogs, after the initial selection of bulls 110 00:10:00,000 --> 00:10:03,000 You can get acquainted with detailed data. 111 00:10:03,000 --> 00:10:06,000 regarding the valuation of each bull 112 00:10:06,000 --> 00:10:09,000 and compare several selected individuals. 113 00:10:09,000 --> 00:10:12,000 Each bull has its own card, 114 00:10:12,000 --> 00:10:15,000 where you can get to know, among other things, his pedigree. 115 00:10:15,000 --> 00:10:18,000 This is the data of RORY's bull. 116 00:10:18,000 --> 00:10:21,000 Here are the pedigrees of the cow and selected bulls. 117 00:10:21,000 --> 00:10:24,000 from the database with the highest breeding value for longevity. 118 00:10:24,000 --> 00:10:28,000 Therefore, the cow and selected bulls do not have common ancestors. 119 00:10:28,000 --> 00:10:31,000 Therefore, they can also be selected for association. 120 00:10:31,000 --> 00:10:34,000 Thank you for your attention.